Sin^4x+2sin^2x=3

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Solution for Sin^4x+2sin^2x=3 equation: 


Simplifying
Sin4x + 2sin2x = 3

Reorder the terms:
2in2sx + in4xS = 3

Solving
2in2sx + in4xS = 3

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Reorder the terms:
-3 + 2in2sx + in4xS = 3 + -3

Combine like terms: 3 + -3 = 0
-3 + 2in2sx + in4xS = 0

The solution to this equation could not be determined.

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